Question

A man bought an article for Rs. x and sold it for Rs. 16. If his loss was x percent, find the cost price of the article.

Answer 1

C.P=Rs x , S.P=Rs. 16

Loss=C.P−S.P=Rs (x−16)

Loss percent=loss/C.P×100

$x=\frac{x-16}{x}\times 100$

$x^2=100x-1600$

$x^2-100x+1600=0$

$x^2-80x-20x+1600=0$

$x(x-80)-20(x-80)=0$

$(x-20)(x-80)=0$

$x=20orx=80$

For x=80 ,
loss % will be more than x% .
So , x=20 Cost price of the article is Rs. 20 .