Question

A man buys $m$ articles at Rs. $x$ each and another $n$ articles for Rs. $y$. If he sells all the articles at Rs. $z$ per article, frame an equation to find his profit

• A. $(mx+n)z-(mx+y)$
• B. $(m+n)zx-(mx+y)$
• C. $(m+n)z-(mx+ny)$
• D. $(mn+x)z-(mx+y)$

Answer 1

The correct option is C $(m+n)z-(mx+ny)$

Cost price for a article is Rs $x$
Cost price of $m$ articles is Rs $mx$.
Cost price of another articles is Rs $y$
Cost price of $n$ another articles is Rs $ny$
Total cost price $=$ Rs $mx+ny$
Selling price of a article is Rs $z$
Therefore Selling Price for $(m+n)$ articles $=$ $z(m+n)$
Profit $=$ Selling price $-$ Cost price
Profit $=z(m+n)-(mx+ny)$