A man buys milk at 60 P per litre, adds one-third of water to it and sells the mixture at 72 P per litre. The profit per cent is_____.

Open in App

Solution

Original volume $= 1 L$
New volume $= 1 + \frac{1}{2} = \frac{4}{3} L$
$C p = 60 P / L$
$S p = 72 P / L$
$\frac{4}{3} L \to 60$
$1 L \to \frac{60 \times 3}{4} = 45$ Rs. (New CP)
Profit $% = \frac{s p - c p}{c p} \times 100$
$= \frac{72 - 45}{45} \times 100$
$= 60 %$ .

Suggest Corrections

Similar questions

Q. A milkman buys milk at Rs.

25

per litre and adds

\frac{1}{4}

of water to it and sells the mixture at Rs.

25

per litre. His gain (in %) is:

Q. A milkman purchases milk at the rate of Rs. 12 per litre and then mixes 25 per cent water to it. Find his profit per cent, if he sells the mixture at Rs. 15 per litre.

A man purchases milk at Rs 8.5 per litre. He dilutes it with water and sells the mixture at the same price, earning a profit of 11.11 $%$ . The amount of water mixed per litre of milk is?

A dairyman pays Rs. 6.40 per litre of milk. He adds water and sells the mixture at Rs. 8 per litre, thereby making 37.5% profit. The proportion of water to milk received by the customers is:

A man bought 20 litres of milk at 4 rupee per litre . He adds 2 litre water to it so as to make it 22 litre. At what rate per litre should he sell the milk so that he gets a profit of 10%.

Join BYJU'S Learning Program

A man buys milk at 60 P per litre, adds one-third of water to it and sells the mixture at 72 P per litre. The profit per cent is_____.

Original volume =1LNew volume =1+12=43LCp=60P/LSp=72P/L43L→601L→60×34=45Rs. (New CP)Profit %=sp−cpcp×100=72−4545×100=60%.

Original volume $= 1 L$
New volume $= 1 + \frac{1}{2} = \frac{4}{3} L$
$C p = 60 P / L$
$S p = 72 P / L$
$\frac{4}{3} L \to 60$
$1 L \to \frac{60 \times 3}{4} = 45$ Rs. (New CP)
Profit $% = \frac{s p - c p}{c p} \times 100$
$= \frac{72 - 45}{45} \times 100$
$= 60 %$ .