A man buys oranges at 9 for Rs.16 and sells 11 for Rs.20. What does he gain or lose per cent?
The correct option is D (2311)%
Given, a man buys 9 oranges for Rs. 16
So, the cost price(C.P) of each orange is Rs.169
And also, he sells 11 oranges for Rs.20.
So, the selling price(S.P) of each orange is 2011
To find gain or loss, we need to compare both the fractions 169 and 2011.
LCM of 11 and 9 is 99
Consider169×1111=17699 and 2011×99=18099
Since, 180>176
⇒18099>17699
∴2011>169
Thus, S.P is greaten than C.P.
So, the man gets profit and the gain(profit) amount =S.P−C.P
=2011−169
=18099−17699
=499
Therefore, profit percentage =profitC.P×100
=(499)(169)×100
=499×916×100
=2511
=2311%