Question

A man buys two cows at 42500 and sold one of them at loss of 10% and sold other at profit of 10% find selling price of each cows if the cost price of both is the same?

Answer 1

cost of 2 cows =42500
the cost price of both is the same
.
so cost of 1 cow =42500/2 =21250

Now one cow was sold at 10% loss
ie;
10% of cost = (21250* 10/100) = 2125
So he sold at a price = 21250-2125=19125

Now the next cow was sold for 21250+2125= 23375

So the cost of cows are Rs.19125 and Rs.23375