A man can row 40 km upstream and 55 km downstream in 13 hours. He can also row 30 km upstream and 44 km downstream in 10 hours. Find the speed of the boat in still water and the speed of the current.
8 km/hr, 3 km/hr
Let the speed of boat in still water be x km/hr and speed of current be y km/hr.
Speed upstream = (x - y)km/hr and speed downstream = (x + y)km/hr.
40x−y+55x+y=13 and 30x−y+44x+y=10Let 1x−y=u and 1x+y=v
The equations reduce to
40u+55v=13 and 30u+44v=10
On writing the equations in standard form, we get
40u+55v−13=0
30u+44v−10=0
By cross multiplication, we get
u55×(−10)−44×(−13)=−v40×(−10)−30×(−13)=144×40−55×30⇒ u−550+572=−v−400+390=11760−1650⇒ u22=v10=1110⇒ u=22110=15 and v=10110=111
So, u=15=1x−y⇒x−y=5 . . . (1)
and v=111=1x+y⇒x+y=11 . . . (2)
On adding (1) & (2), we get
2x=16 ⇒ x=8
and putting x = 8 in (1), we get,
8−y=5 ⇒ y=3.
∴ Speed of the boat in still water is 8km/hr and speed of the current is 3 km/hr.