A man can swim at 4m/s in a still water swimming pool. He enters a 200m wide river at one bank and swims (w.r.t. water) at an angle of 60 degree to the river flow velocity. The river flow velocity 5m/s. In how much time does he cross the river Calculate his drift

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Solution

Dear student,

$V e l o c i t y o f t h e s w i m m e r t o w a r d s t h e r i v e r b a n k v = v_{1} \sin θ t i m e t a k e n = \frac{200}{v_{1} \sin θ} = \frac{200}{4 \sin 60} t = \frac{200}{4 \times \frac{\sqrt{3}}{2}} = \frac{100}{\sqrt{3}} t = 57.7 s e c$

$D r i f t = s p e e d o f t h e r i v e r \times t i m e D r i f t = 5 \times 57.7 D r i f t = 288.5 m$

Regards

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A man can swim at 4m/s in a still water swimming pool. He enters a 200m wide river at one bank and swims (w.r.t. water) at an angle of 60 degree to the river flow velocity. The river flow velocity 5m/s. In how much time does he cross the river Calculate his drift

Dear student, Velocity of the swimmer towards the river bankv=v1sinθtime taken=200v1sinθ=2004sin60t=2004×32=1003t=57.7sec Drift=speed of the river×timeDrift=5×57.7Drift=288.5m Regards