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Question

# A man can swim at a speed of 3kmh−1 in still water, he wants to cross a 500m wide river flowing at 2kmh−1. He keeps himself always at an angle of 120o with the river flow while swimmingChoose the correct options

A
The time taken to cross the river is 133h
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B
The time taken to cross the river is 123h
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C
The drift of the man along the direction of flow, when he arrives at the opposite bank is 163km
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D
The drift of the man along the direction of flow, when he arrives at the opposite bank is 133km
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Solution

## The correct options are A The time taken to cross the river is 13√3h C The drift of the man along the direction of flow, when he arrives at the opposite bank is 16√3kmWe know v=dtt=dv=12vcos30o=123√12=13√3hrsas you know indirection the are two velocities one is given & another is velocities components So Vmean=Vgiven=Vsin30∘=2−3sin30∘=2−32=12drift =vt=12×13√3=13√3km

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