A man carrying a bag of mass $25 kg$ climbs up to a height of $10 m$ in $50 s$ . The power delivered by him to the bag is
$[Take g = 9.8 {m/s}^{2}]$

64 W

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36 W

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49 W

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23 W

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Solution

The correct option is C $49 W$
We know, power,
$P = \frac{Work done}{time taken} = \frac{m g h}{t}$
$\Rightarrow P = \frac{25 \times 9.8 \times 10}{50} = 49 W$

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A person carrying a bag of total mass 25 kg climbs up to height of 5 m in 30 seconds slowly. The power delivered for carrying the bag is-

A man of mass 50 kg climbs up a ladder of height 10 m. Calculate:

(i) the work done by the man, and

(ii) the increase in his potential energy. (g = 9.8 m $s^{- 2}$ ).

s^{- 2}

50

5

10

[g = 10 m / s^{2}]

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