A man claps his hands near a mountain and hears an echo after 4 seconds. If the speed of sound be 330m/s; calculate the distance of the mountain from the man.

Open in App

Solution

$Distance, d = \frac{vt}{2} = \frac{330 \times 4}{2} = 660 m$

Suggest Corrections

Similar questions

a man slaps his hand near a mountain and hears the Eco after 4 seconds. if the speed of sound under these conditions be 330 meter per second what is the distance of mountains from the man :-

A) 660 m

B) 440 m

C) 330 m

D) 550 m

Q. A man standing between two cliffs hears the first echo of sound after 2 seconds and the second echo 2 seconds after the initial sound. If the speed of sound be 330 m s

^{- 1}

, the distance between the two cliffs should be :

Q. A man, standing between two cliffs, claps his hands and starts hearing a series of echoes at intervals of one second. If the speed of sound in air is

340 m s^{- 1}

, the distance between the cliffs is?

Q. Statement I: Avinash is standing at a distance of 33 m from a wall. He claps and hears the echo of his own clap. (Take the speed of sound in air as 330 m

s^{- 1}

)
Statement II: To hear an echo, the sound after reflection should reach the ear at least 0.1 seconds after the original sound is heard.

Join BYJU'S Learning Program

A man claps his hands near a mountain and hears an echo after 4 seconds. If the speed of sound be 330m/s; calculate the distance of the mountain from the man.

Distance, d =vt2 =330×42 =660 m

$Distance, d = \frac{vt}{2} = \frac{330 \times 4}{2} = 660 m$