Question

A man does a given amount of work in 10 s. Another man does the same amount of work in 20 s. The ratio of the output power of the first man to the second man is

• A. $1$
• B. $\frac{1}{2}$
• C. $\frac{2}{1}$
• D. None of these

Answer 1

The correct option is C

$\frac{2}{1}$

The explanation for the correct option:

Here given,

The time that is taken by the first man $(T_1)$ = $10$ seconds

The time is that taken by the second man $(T_2)$ = $20$ seconds

We know,

$P=\frac{W}{t}$

$\Rightarrow P\alpha \frac{1}{t}$ (1)

Let the power output for the first man be $P_1$

and the power output for the second man be $P_2$

From equation (1),

$\frac{P_1}{P_2}=\frac{T_1}{T_2}$

$\Rightarrow \frac{P_1}{P_2}=\frac{20}{10}$

$\Rightarrow \frac{P_1}{P_2}=\frac{2}{1}$

Therefore, the ratio of the output power of the first man to the second man is $\frac{2}{1}$

Hence, Option (C) is the correct answer.