Question

A man does a given amount of work in $10sec$. Another man does the same amount of work in $20sec$. The ratio of the output power of first man to the second man is $\frac{x}{y}$ Find $(x-y)$.

Answer 1

Formula Used: $P=\frac{w}{t}$

Power $=\frac{w}{t}$
If $W$ is constant, then $P\propto \frac{1}{t}$

i.e. $\frac{P_1}{P_2}=\frac{t_2}{t_1}=\frac{20}{10}=\frac{2}{1}$

As per question $x-y=1$

Final Answer: $1$