Question

A man drives $3$ km towards north and then $4$ km towards east. How far is he away from his initial position?

Answer 1

R.E.F image

By Pythagoras theorem,

$O{B}^2=O{A}^2+A{B}^2$

$\Rightarrow O{B}^2=3^2+4^2=9+16=25$

$\Rightarrow OB=5km$