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Question

A man driving his moped at 24 kmph reaches his destination 5 minutes late to an appointment. If he had driven at 30 kmph he would have reached his destination 4 minutes before time. How far is his destination?

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Solution

Let the distance be 'x' km
Therefore time taken to cover 'x' km at 24 kmph =x24 hr
Time taken to cover 'x'km at 30 kmph =x30 hr
But it is given that the difference between two timinings =9min=960 hr
x24x30=960
5x4x120=960
x120=960
x=960×120=18
Therefore the distance is 18 km.

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