A man earned Rs- 80- He spent Rs- 1335 on food- 2512 on shopping and Rs- 425 on groceries- How much did he save-

A] Total earned = Rs. 80 #160; #160; Amount carned = 80 (133/5+251/2 + 42/5) #160; #160; #160; #160; #160; #160; #160; #160; ...

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Standard VI

Mathematics

Addition of Fractions

A man earned ...

Question

A man earned $R s . 80$ . He spent $R s . 13 \frac{3}{5}$ on food, $25 \frac{1}{2}$ on shopping and $R s . 4 \frac{2}{5}$ on groceries. How much did he save.

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Solution

A] Total earned = Rs. 80

Amount carned $= 80 - (13 \frac{3}{5} + 25 \frac{1}{2} + 4 \frac{2}{5})$

$= 80 - (\frac{68}{5} + \frac{51}{2} + \frac{22}{5})$

$= 80 - (\frac{90}{5} + \frac{51}{2}) = 80 - (\frac{180 + 1255}{10})$

$= 80 - (\frac{435}{10}) = 80 - 43.5 = 36.5 R s$

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A man earned Rs.80. He spent Rs.1335 on food, 2512 on shopping and Rs.425 on groceries. How much did he save.

A] Total earned = Rs. 80 Amount carned =80−(1335+2512+425) =80−(685+512+225) =80−(905+512)=80−(180+125510) =80−(43510)=80−43.5=36.5Rs

A man earned $R s . 80$ . He spent $R s . 13 \frac{3}{5}$ on food, $25 \frac{1}{2}$ on shopping and $R s . 4 \frac{2}{5}$ on groceries. How much did he save.

A] Total earned = Rs. 80

Amount carned $= 80 - (13 \frac{3}{5} + 25 \frac{1}{2} + 4 \frac{2}{5})$

$= 80 - (\frac{68}{5} + \frac{51}{2} + \frac{22}{5})$

$= 80 - (\frac{90}{5} + \frac{51}{2}) = 80 - (\frac{180 + 1255}{10})$

$= 80 - (\frac{435}{10}) = 80 - 43.5 = 36.5 R s$