A man fires a gun and hears the echo from the cliff after 2 seconds. He walks towards cliff about a distance of 85 m and fires the gun again. He hears echo after 1.5 seconds. In this case, the velocity of sound in air is

85 m/s

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170 m/s

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340 m/s

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680 m/s

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Solution

The correct option is C 340 m/s
Let the distance of the man from the cliff be 'd', then
$V = \frac{2 d}{t}$
$V = \frac{2 d}{2} \Rightarrow V = d$
Similarly, in case - 2
$V = \frac{2 (d - 85)}{t}$
$V = \frac{20 (v - 85)}{15}$
$\Rightarrow 3 V = 4 v - 340$
$v = 340 m / s$

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A man fires a gun and hears the echo from the cliff after 2 seconds. He walks towards cliff about a distance of 85 m and fires the gun again. He hears echo after 1.5 seconds. In this case, the velocity of sound in air is

The correct option is C 340 m/sLet the distance of the man from the cliff be 'd', then V=2dt V=2d2⇒V=d Similarly, in case - 2 V=2(d−85)t V=20(v−85)15 ⇒3V=4v−340 v=340m/s

The correct option is C 340 m/s
Let the distance of the man from the cliff be 'd', then
$V = \frac{2 d}{t}$
$V = \frac{2 d}{2} \Rightarrow V = d$
Similarly, in case - 2
$V = \frac{2 (d - 85)}{t}$
$V = \frac{20 (v - 85)}{15}$
$\Rightarrow 3 V = 4 v - 340$
$v = 340 m / s$