A man fires a gun while standing between 2 parallel hills. If he hears the first echo after 2s and second echo after 3s, then what is the distance between the hill (velocity of sound is 330m/s)

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Solution

Time of echo = 2 s and 3 s

speed of sound = 330 m/s

Distance of left cliff
$= s p e e d \times t i m e ⟶ 330 \times 2 s e c = 660 m$
$2 d_{1} = 660$
$d_{1} = 330 m$

Distance of right cliff
$= s p e e d \times t i m e ⟶ 330 \times 3 s e c = 990 m$
$2 d_{2} = 990$
$d_{2} = 495 m$
$T o t a l d i s t a n c e b e t w e e n t h e h i l l s = 330 + 495 = 825 m$

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A man fires a gun while standing between 2 parallel hills. If he hears the first echo after 2s and second echo after 3s, then what is the distance between the hill (velocity of sound is 330m/s)

Time of echo = 2 s and 3 s speed of sound = 330 m/s Distance of left cliff =speed×time⟶330×2sec=660m2d1=660d1=330m Distance of right cliff =speed×time⟶330×3sec=990m 2d2=990d2=495m Totaldistancebetweenthehills=330+495=825m