A man goes 100 m North then 100 m East and then 20 m North and then 100 -2 m South West- Find the displacement-A- 20 m WestB- 20 m EastC- 20 m NorthD- 20 m South

Going 50 m to the South of her house, Radhika turns left and goes another 20 m. Then turning to the North, she goes 30 m and then starts walking to her house. In which direction is she walking now?

Q. Four particles

A, B, C

and

D

are in motion. The velocities of one with respect to other are given as

{\to v}_{D C}

20 m/s

towards north,

{\to v}_{B C}

20 m/s

towards east and

{\to v}_{B A}

20 m/s

towards south. Then

{\to v}_{D A}

I am facing South. I turn right and walk 20 m. Then I turn right again and walk 10 m. Then I turn left and walk 10 m and then turning right walk 20 m. Then I turn right again and walk 60 m. Which direction am I facing now ?

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A man goes 100 m North then 100 m East and then 20 m North and then 100√2 m South West. Find the displacement.

The correct option is C 20 m NorthThe total displacement is the summation of all the position vectors. Also note that 100√2 South West can be written as −100^i−100^j d=100^j+100^i+20^j+(−100^i−100^j) =20^j

A man goes $100 m$ North then $100 m$ East and then $20 m$ North and then $100 \sqrt{2} m$ South West. Find the displacement.

The correct option is C $20 m$ North
The total displacement is the summation of all the position vectors.
Also note that $100 \sqrt{2}$ South West can be written as
$- 100^i - 100^j$
$d = 100^j + 100^i + 20^j + (- 100^i - 100^j)$
$= 20^j$