A man goes 100m North then 100m East and then 20m North and then 100√2m South West. Find the displacement.
A
20m West
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B
20m East
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C
20m North
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D
20m South
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Solution
The correct option is C20m North The total displacement is the summation of all the position vectors.
Also note that 100√2 South West can be written as −100^i−100^j d=100^j+100^i+20^j+(−100^i−100^j) =20^j