Question

A man goes $40$ m due north and then $50$ m due west. Find his distance from the starting point.

Answer 1

From the diagram, distance between $A$ to $C$, is the hypotenuse of a right angled triangle.
${AC}^2={50}^2+{40}^2$
$=>{AC}^2=4100$
$=>AC=64.03$ m