Question

A man goes at the top of smooth inclined plane. He releases a bag to fall freely and himself slides down on an inclined plane to reach the bottom. If $u_1$ and $u_2$ are the respective velocities of the man and bag at the bottom of inclined plane, then:

• A. $u_1>u_2$
• B. $u_1<u_2$
• C. $u_1=u_2$
• D. $u_1$ and $u_2$ cannot be compared

Answer 1

Answer: (C)

$u_1=u_2$

As the bag and the person both move down the smooth inclined plane, the potential energy of the person and the bag will be converted into their respective kinetic energies.

The conversion of the energy for the person and the ball can be shown as:

$KE=PE$

$\frac{1}{2}m{v}^2=mgh$

$v=\sqrt{2gh}$

Since the height through which the person and the bag is same, so their velocities at the bottom will be same.

Option $C$ is correct.