A man goes to a place at the rate of $4 k m$ per hour. He comes back on a bicycle at $16 k m$ per hour. His average speed in km per hour for the entire journey is

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Solution

The correct option is B $6.4$
The man goes at the rate of 4 km/hour and comes back at 16 km/hour,
We know, average speed $= (\frac{product of speed}{sum of speed} \times 2) = 2 \times (\frac{4 \times 16}{4 + 16}) = \frac{2 \times 64}{20} = 6.4 k m / h o u r .$
$∴$ option B is correct.

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A man goes to a place at the rate of 4 km per hour. He comes back on a bicycle at 16 km per hour. His average speed in km per hour for the entire journey is

The correct option is B 6.4The man goes at the rate of 4 km/hour and comes back at 16 km/hour,We know, average speed =(product of speedsum of speed×2)=2×(4×164+16)=2×6420=6.4km/hour.∴ option B is correct.

A man goes to a place at the rate of $4 k m$ per hour. He comes back on a bicycle at $16 k m$ per hour. His average speed in km per hour for the entire journey is

The correct option is B $6.4$
The man goes at the rate of 4 km/hour and comes back at 16 km/hour,
We know, average speed $= (\frac{product of speed}{sum of speed} \times 2) = 2 \times (\frac{4 \times 16}{4 + 16}) = \frac{2 \times 64}{20} = 6.4 k m / h o u r .$
$∴$ option B is correct.