A man has a box of weight $10 k g$ . The energy of the box, when the man runs with a constant velocity of $2 m / s e c$ along with the box behind the bus, is:

10 j o u l e s

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30 j o u l e s

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20 j o u l e s

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2 j o u l e s

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Solution

The correct option is C $20 j o u l e s$
when the man runs with the box $(m = 10 k g)$
with a velocity of V = 2m/s ,
it giains KE as :
KE= $\frac{1}{2} m v^{2} = \frac{1}{2} \times 10 \times (2)^{2} = 20 J$

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A man has a box of weight 10 kg. The energy of the box, when the man runs with a constant velocity of 2 m/sec along with the box behind the bus, is:

The correct option is C 20 jouleswhen the man runs with the box (m=10kg) with a velocity of V = 2m/s , it giains KE as :KE=12mv2=12×10×(2)2=20J

A man has a box of weight $10 k g$ . The energy of the box, when the man runs with a constant velocity of $2 m / s e c$ along with the box behind the bus, is:

The correct option is C $20 j o u l e s$
when the man runs with the box $(m = 10 k g)$
with a velocity of V = 2m/s ,
it giains KE as :
KE= $\frac{1}{2} m v^{2} = \frac{1}{2} \times 10 \times (2)^{2} = 20 J$