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Question

A man has only 20 paise coin and 25 Paisa coin in his purse if he has 50 coins in all totally rupees 11.25 how many coins of each kind does he have

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Solution

Let no. of 20 paise coins is x and no. of 25 paise coins is y. Then by the given question,
x+y=50 --------------------(1) and
20x+25y=1125 [∵, Rs. 11.25=1125 paise]
or, 4x+5y=225 -----------(2)
Multiplying (1) with 4 we get,
4x+4y=200 ---------------(3)
Subtracting (3) from (2) we get,
y=25
Putting in (1)
x=50-y=50-25=25
∴, x=25, y=25
.

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