Question

A man has to build a rhombus shaped swimming pool. One of the diagonal is 13 m and the other is twice the first one. Then find the area of the swimming pool and also find the cost of cementing the floor at the rate of ₹ 15 per sq.m.

Answer 1

Length of one of the diagonal, $d_1=13m$

Length of the other diagonal, $d_2=2\times d_1$$\Rightarrow d_2=2\times 13=26m$

(1 mark)
We know that, if two diagonals are given the area of the Rhombus $=\frac{1}{2}\times d_1\times d_2=\frac{1}{2}\times 13\times 26sqm=13\times 13sqm=169sqm$
The cost of cementing the floor is ₹ 15 per sq m

(1 mark)
So, the cost of cementing 169 sq m = 169 × ₹ 15 = ₹ 2535.

Hence the cost of cementing the floor of 169 sq m is ₹ 2535.
(1 mark)