A man having defective eye is unable to see anything closer than $40 c m$ . The person is suffering from ___ and the power of appropriate lens to correct his vision is _

Hypermetropia,

+ 1.5 D

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Myopia,

- 1.5 D

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Myopia,

+ 1.5 D

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Hypermetropia,

1.5 D

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Solution

The correct option is A Hypermetropia, $+ 1.5 D$
$\frac{1}{f} = \frac{1}{- 40} - \frac{1}{- 25}$
$\frac{1}{f} = \frac{8 - 5}{200} = \frac{3}{200}$
$P = \frac{100}{f} = \frac{300}{200} = + 1.5 D$

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A man having defective eye is unable to see anything closer than 40 cm. The person is suffering from _______ and the power of appropriate lens to correct his vision is _____

The correct option is A Hypermetropia, +1.5 D1f=1−40−1−25 1f=8−5200=3200 P=100f=300200=+1.5 D

A man having defective eye is unable to see anything closer than $40 c m$ . The person is suffering from ___ and the power of appropriate lens to correct his vision is _

The correct option is A Hypermetropia, $+ 1.5 D$
$\frac{1}{f} = \frac{1}{- 40} - \frac{1}{- 25}$
$\frac{1}{f} = \frac{8 - 5}{200} = \frac{3}{200}$
$P = \frac{100}{f} = \frac{300}{200} = + 1.5 D$