A man in a ballon rising vertically with an acceleration of 4.9msec2 releases a ball 2 sec after the balloon is let go from the ground. The greatest height above the ground reached by the ball is (g=9.8msec2)
A
14.7 m
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B
19.6 m
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C
9.8 m
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D
24.5 m
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Solution
The correct option is A 14.7 m Height travelled by ball (with balloon) in 2 sec h1=12at2=12×4.9×22=9.8m Velocity of the balloon after 2 sec v=at=4.9×2=9.8ms Now if the ball is released from the balloon then it acquire same velocity in upward direction. Let it move up to maximum height h2 v2=u2−2gh2⇒0=(9.8)2−2×(9.8)×h2∴h2=4.9m Greatest height above the ground reached by the ball = h1+h2=9.8+4.9=14.7m