A man invested ₹ 1000 for 3 years at 11per cent simple interest per annum and ₹1000 at 10 % compounded interest per annum compounded annually for three years. Find which investment is better.
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Solution
for simple interest final investment value A = P(1+RT) P: Initial investment = 1000 R rate of interet = 11% = .11 T: time = 3 years A = 1000(1+.11*3) = 1330 rs
for compund interest finl interest A = P(1+R)^T R = 10% = .1 T = 3 years A= 1000(1+ 0.1)^3 = 1331 rupees Thus the second investment is better as it has higher final amount even thugh the rate of interest is lower