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1st Equation of Motion

A man is 45 m...

Question

A man is 45m behind the bus, when the bus start accelerating from rest with acceleration $2.5 m / s^{2}$ . With what minimum velocity should the man start running to catch the bus?

A

12 m/s

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B

14 m/s

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C

15 m/s

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D

16 m/s

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Solution

The correct option is C 15 m/s

Bus starts from rest
$v^{2} = u^{2} + 2 a s v^{2} = 0 + 2 \times 2.5 \times 45 v^{2} = 5 \times 45 v^{2} = 225 v = 15 m / s$

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