wiz-icon
MyQuestionIcon
MyQuestionIcon
2
You visited us 2 times! Enjoying our articles? Unlock Full Access!
Question

A man is coming down an incline of angle 30. When he walks with speed 3m/s he has to keep his umbrella vertical w.r.t. ground to protect himself from rain. The actual speed of rain is 5 m/s. At what angle with vertical should he keep his umbrella when he is at rest so that he does not get drenched?


A

θ=57

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

θ=37

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C

θ=30

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

θ=45

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B

θ=37


vman=23cos30^i23sin30^j

vm=3^i3^j

At this moment the rain appears to him as vertical.Let the magnitude of |vrm|=v

vrm=v^j

vrm=vrvm

vr=vrm+vm

Draw vector diagram

|vr|=5

Given now from it we know

vr=5 sin θ ^i5cos θ^j

vr=vrm+vm

5 sinθ^i=v^j+3^i3^j

(5sinθ=3) -------------(1)

5cosθ=(v+3)

From equation (1) we know sinθ=35

θ=37


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Relative Motion in 2D
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon