Total amount to be counted =Rs. 10710
A man counts Rs. 180 per minute for half an hour
Amount counted in half an hour =180×30=Rs. 5400
Amount to be counted =Rs. 10710−Rs. 5400=Rs. 5310
It is also given that after half an hour Rs. 3 gets
less every minute than the preceding minute.
i.e., 177+174+171+......+3=5310
Now this forms an arithmetic progression
where a=177 d=3
sum of n terms of A.P=5310
Sn=n2[a+l]=5310
⇒n2[177+3]=5310
⇒n=59
Total time =30+59=89 minutes