Question

A man is five times as old as his son. In two years time, he will be four times as old as his son. Find their present ages.

Answer 1

Let, the present age of a man $=x$ years

and the present age of his son $=y$ years

According to the question,

$x=5y$ and $x+2=4(y+2)$

$\because x+2=4(y+2)$

$⟹5y+2=4y+8$

$⟹5y-4y=8-2$

$\therefore y=6$

Hence, $x=5y=5\left(6\right)=30$

i.e., the present age of a man $=30$ years

and the present age of his son $=6$ years