A man is known to speak truth is 75% cases. If he throws an unbiased die and tells his friend that it is a six, then the probability that it is actually a six, is
A
16
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
18
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
34
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
38
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is D38 Let E denote the event that a six occurs and A be the event theat the man reports that it is a six. We have P(E)=16,P(E′)=56,P(AE)=34 and P(AE′)=14. By Baye’s theorem P(EA)=P(E).P(AE)P(E).P(AE)+P(E′).P(AE′)=(16)(34)(16)(34)+(56)(14)=38