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Question

A man is raising himself and the crate on which he stands with an acceleration of 5ms−2 by a massless rope-and-pulley arrangement. Mass of the man is 100kg. If g=10ms−2,, the contact force between the man and the crate is:
980562_dbaa595141324b159b809cb9a743c2f3.PNG

A
2250N
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B
1125N
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C
750N
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D
375N
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Solution

The correct option is D 375N
(D)
When the man applies a force of T, the string creates equal force T as tension. The same tension T acts on the crate too.
Total force acting on the system will become 2T.
2T150g=150×5
T=1125N
The man applies a force of 1125 N on the rope.
The constant force between the man and the crate is given by,
constant force, F= Weight of man + crate force applied by man.
=150g1125
=15001125
=375N.

1086723_980562_ans_2ed6609913b34691be249bc03245938d.jpg

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