A man is raising himself and the crate on which he stands with an acceleration of 5ms−2 by a massless rope-and-pulley arrangement. Mass of the man is 100kg. If g=10ms−2,, the contact force between the man and the crate is:
A
2250N
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B
1125N
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C
750N
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D
375N
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Solution
The correct option is D375N
(D)
When the man applies a force of T, the string creates equal force T as tension. The same tension T acts on the crate too.
∴ Total force acting on the system will become 2T.
⇒2T−150g=150×5
⇒T=1125N
∴ The man applies a force of 1125N on the rope.
The constant force between the man and the crate is given by,
constant force, F= Weight of man + crate − force applied by man.