A man is standing between hill A and hill B, claps louder. He hears an echo after $4$ seconds from hill A and after $6$ seconds from hill B. The speed of sound in air is $340 m s^{- 1}$ . Calculate the distance between the two hills.

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Solution

Given,
Speed of sound $v = 340 m / s$

Time to hrar echo $t_{1} = 4 s t_{2} = 6 s$

Total distance travel by sound to hear echo from hill A $d_{a} = 2 x$

Total distance travel by sound to hear echo from hill B $d_{b} = 2 y$

Distance of Hill A from man is, $x = \frac{v \times t}{2} = \frac{4 \times 340}{2} = 680 m$

Distance of Hill B from man is, $y = \frac{v \times t}{2} = \frac{6 \times 340}{2} = 1020 m$

So distance between Hill A and B is, $d = x + y = 680 + 1020 = 1700 m$

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A man is standing between hill A and hill B, claps louder. He hears an echo after 4 seconds from hill A and after 6 seconds from hill B. The speed of sound in air is 340ms−1. Calculate the distance between the two hills.

A man is standing between hill A and hill B, claps louder. He hears an echo after $4$ seconds from hill A and after $6$ seconds from hill B. The speed of sound in air is $340 m s^{- 1}$ . Calculate the distance between the two hills.