Question

A man is standing between two parallel cliffs and fires a gun. If he hears first and second echoes after $1.5s$ and $3.5s$ respectively, the distance between the cliffs is (Velocity of sound in air = $340m{s}^{-1}$)

• A. 1190 m
• B. 850 m
• C. 595 m
• D. 510 m

Answer 1

The correct option is B

850 m

$d$ = $d_1+d_2$ = $\frac{V}{2}(t_1+t_2)$ = $\frac{340}{2}(1.5+3.5)$

= $850m$