A man is standing in lift which goes up and comes down with the same constant acceleration. If the ratio of the apparent weights in the two cases is 2:1, then the acceleration of the lift is
A
3.33ms−2
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B
2.50ms−2
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C
2.00ms−2
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D
1.67ms−2
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Solution
The correct option is C3.33ms−2 m(g+a)m(g−a)=21⇒g+a=2g−2a⇒a=g3=103=3.33m/s2Ans.(A)