A man is walking along a straight road. He notices the top of a tower subtending an angle A = 60 $^{\circ}$ with the ground at the point where he is standing. If the height of the tower is h = 30 m, then what is the distance (in meters) of the man from the tower (Use $\sqrt$ 3 = 1.732)?

15.23

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17.32

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25.32

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None of these

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Solution

The correct option is B
17.32

Let BC represent the tower with height h = 30 m and A represent the point where the man is standing.

AB = d denotes the distance of the man from the tower.

The angle subtended by the tower is A = 60 $^{\circ}$ .

From trigonometry, tan A = tan 60 $^{\circ}$ = h/d = $\sqrt{}$ 3. So, d = 30/ $\sqrt{}$ 3 m.

Hence, the distance of the man from the tower is 17.32 m.

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A man is walking along a straight road. He notices the top of a tower subtending an angle A = 60∘ with the ground at the point where he is standing. If the height of the tower is h = 30 m, then what is the distance (in meters) of the man from the tower (Use √3 = 1.732)?

A man is walking along a straight road. He notices the top of a tower subtending an angle A = 60 $^{\circ}$ with the ground at the point where he is standing. If the height of the tower is h = 30 m, then what is the distance (in meters) of the man from the tower (Use $\sqrt$ 3 = 1.732)?