A man is walking due west at the rate of 5km/h.The rain appears to him to come down vertically at the rate of 5km/h. The actual velocity and direction of rainfall with the vertical respectively are
A
5√2km/h,45o
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B
1√2km/h,30o
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C
5km/h,0o
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D
1km/h,90o
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Solution
The correct option is A5√2km/h,45o VRain,Person=VRain−VPerson=−5^j (vertically down) Thus, VRain−(−5^i)=−5^j (west means −5^i) or, VRain=−5^i−5^j Thus, magnitude = 5√2 km/hr, direction is in 3rd quadrant, i.e. clockwise to vertical at an angle of tan−1(55)=45o to vertical