A man lifts a luggage of $10 k g$ from the ground and puts it on his head $1.7 m$ above the ground. Calculate work done by man on the luggage. Take acceleration due to gravity $g = 10 m / s^{2}$

180 J

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200 J

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150 J

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170 J

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Solution

The correct option is D
170 J

Given,

Mass of luggage $m$ = $10 k g$

Displacement $s$ = $1.7 m$

Force (F) acting on luggage = $m g$ = $100 N$

To lift the luggage man has to apply equal and opposite force to weight of luguagge.
Work done by the man on the luggage = $F \times s$

$F = 100 N$ & $s = 1.7 m$
Work done = $100 \times 1.7$ = $170 J$

Hence the required work done is $170 J$ . It can be noted that the work is done by the man on the luggage because he lifts it against the gravitational force of Earth.

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A man lifts a luggage of 10 kg from the ground and puts it on his head 1.7 m above the ground. Calculate work done by man on the luggage. Take acceleration due to gravity g = 10 m/s2

A man lifts a luggage of $10 k g$ from the ground and puts it on his head $1.7 m$ above the ground. Calculate work done by man on the luggage. Take acceleration due to gravity $g = 10 m / s^{2}$