A man lifts a luggage of 10kg from the ground and puts it on his head 1.7m above the ground. Calculate work done by him on the luggage. Take acceleration due to gravity=10ms−2.
A
150J
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B
170J
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C
180J
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D
200J
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Solution
The correct option is B
170J
Given:
Mass, m=10kg,
Acceleration due to gravity, g=10ms−2,
Displacement, s=1.7m.
Force F is calculated as F=m×g=10×10=100N
Work done by the man on luggage=Force×displacement W=100×1.7=170J
Hence, the required work done is 170J.
It can be noted that the work is done by the man on the luggage because he lifts it against the gravitational force of the earth.