Question

A man lifts a luggage of $10kg$ from the ground and puts it on his head $1.7m$ above the ground. Calculate work done by him on the luggage. Take acceleration due to gravity$=10m{s}^{-2}$.

• A. $150J$
• B. $170J$
• C. $180J$
• D. $200J$

Answer 1

The correct option is B

$170J$

Given:
Mass, $m=10kg$,
Acceleration due to gravity, $g=10m{s}^{-2}$,
Displacement, $s=1.7m$.
Force $F$ is calculated as
$F=m\times g=10\times 10=100N$
Work done by the man on luggage$=Force\times displacement$
$W=100\times 1.7=170J$
Hence, the required work done is $170J$.
It can be noted that the work is done by the man on the luggage because he lifts it against the gravitational force of the earth.