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Question
A man lifts a luggage of 10 kg from the ground and puts it on his head 1.7 m above the ground. Calculate work done by him on the luggage.
Assume acceleration due to gravity g=10 m/s2.
A man lifts a luggage of 10 kg from the ground and puts it on his head 1.7 m above the ground. Calculate work done by him on the luggage.
Assume acceleration due to gravity g=10 m/s2.
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Solution
The correct option is D 170 J
Force applied by the man F is equal to the weight of the body.
Force F = mass × acceleration due to gravity = (10 x 10) N = 100 N
Work done by the man on the luggage = Force x Displacement
F = 100 N and S = 1.7 m
Work done = 100 x 1.7 = 170 J
Hence the work done is 170 J.
It can be noted that the work is done by the man on the luggage because he lifts it against the gravitational force of the Earth.
170 J
Force applied by the man F is equal to the weight of the body.
Force F = mass × acceleration due to gravity = (10 x 10) N = 100 N
Work done by the man on the luggage = Force x Displacement
F = 100 N and S = 1.7 m
Work done = 100 x 1.7 = 170 J
Hence the work done is 170 J.
It can be noted that the work is done by the man on the luggage because he lifts it against the gravitational force of the Earth.
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