Question

Calculate the work done by a man to lift a luggage of 10 kg from the ground to a height of 1.7 m above the ground. Take ($g=9.8m/s^2$)

• A. 180 J
• B. 366.2 J
• C. 266 J
• D. 166.6 J

Answer 1

The correct option is D

166.6 J

In order to raise the luggage, the man has to do work against the force of gravity. Therefore the force required to shift the luggage $F=mg$.
Force (F) = mass(m) x acceleration due to gravity(g) = 10 x 9.8 N = 98 N
Displacement S (vertical height moved) = 1.7m

Work done = $F\times S\times cos\theta$

Here, the direction of force and displacement are in same direction. Hence, $\theta =0$ and $\cos 0=1$
So, work done by the man = F x S

Work done = 98 x 1.7 = 166.6 J

Hence, the required work done is 166.6 J.