A man lifts a luggage of $10 k g$ from the ground and puts it on his head $1.7 m$ above the ground. Calculate work done by him on the luggage. Take acceleration due to gravity $= 10 m s^{- 2}$ .

$150 J$

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$170 J$

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$180 J$

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$200 J$

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Solution

The correct option is B
$170 J$

Given:
Mass, $m = 10 k g$ ,
Acceleration due to gravity, $g = 10 m s^{- 2}$ ,
Displacement, $s = 1.7 m$ .
Force $F$ is calculated as
$F = m \times g = 10 \times 10 = 100 N$
Work done by the man on luggage $= F o r c e \times d i s p l a c e m e n t$
$W = 100 \times 1.7 = 170 J$
Hence, the required work done is $170 J$ .
It can be noted that the work is done by the man on the luggage because he lifts it against the gravitational force of the earth.

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A man lifts a luggage of 10kg from the ground and puts it on his head 1.7m above the ground. Calculate work done by him on the luggage. Take acceleration due to gravity=10ms−2.

A man lifts a luggage of $10 k g$ from the ground and puts it on his head $1.7 m$ above the ground. Calculate work done by him on the luggage. Take acceleration due to gravity $= 10 m s^{- 2}$ .