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Question

A man measures the time period of a simple pendulum inside a stationary lift and finds it to be 10 sec. If the lift accelerates upwards with an acceleration g4, then find the time period of the pendulum.

A
85 sec
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B
45 sec
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C
105 sec
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D
25 sec
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Solution

The correct option is B 45 sec
In a stationary lift T=2πlg=10 seconds ...(1)
For a lift accelerated upwards, the effective value of acceleration due to gravity:
g=g+a
Replacing g by g in Eq.(1),
T=2πl(g+a) ...(2)
From Eq. (1) & (2)
TT=gg+a
TT= gg+g4=45
T=2T5=45 seconds

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