A man moves $20 k m$ down stream in $5$ hours and $10 k m$ up stream in same time. The speed of stream

4 k m / h

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1 k m / h

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1.6 k m / h

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n o n e

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Solution

The correct option is B $1 k m / h$
$\begin{matrix} t = \frac{20}{V + V^{1}} \Rightarrow V + V^{1} = 4 5 = \frac{10}{V - V^{1}} \Rightarrow V - V^{1} = 2 V = 3 V^{1} = 1 s t r e a m 1 k m / h \end{matrix}$

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A man moves 20 km down stream in 5 hours and 10 km up stream in same time. The speed of stream

The correct option is B 1 km/ht=20V+V1⇒V+V1=45=10V−V1⇒V−V1=2V=3V1=1stream1km/h

A man moves $20 k m$ down stream in $5$ hours and $10 k m$ up stream in same time. The speed of stream

The correct option is B $1 k m / h$
$\begin{matrix} t = \frac{20}{V + V^{1}} \Rightarrow V + V^{1} = 4 5 = \frac{10}{V - V^{1}} \Rightarrow V - V^{1} = 2 V = 3 V^{1} = 1 s t r e a m 1 k m / h \end{matrix}$