A man moves on a straight horizontal road with a block of mass 2 kg in his hand . If he covers a distance of 40 m with an acceleration $0.5 m / s^{2}$ , find the work done by the man on the block during the motion.

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Solution

$m_{b} = 2 k g, s = 40 m, a = 0.5 m . s e c^{2}$

So, force applied by the man on the box,

$F = m_{b} a$

$2 \times (0.5)$

$= 1 N$

$ω = F . S$

$= 1 \times 40$

$= 40 J$

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A man moves on a straight horizontal road with a block of mass 2 kg in his hand . If he covers a distance of 40 m with an acceleration 0.5m/s2, find the work done by the man on the block during the motion.

mb=2kg,s=40m,a=0.5 m.sec2 So, force applied by the man on the box, F=mba 2×(0.5) =1N ω=F.S =1×40 =40 J

A man moves on a straight horizontal road with a block of mass 2 kg in his hand . If he covers a distance of 40 m with an acceleration $0.5 m / s^{2}$ , find the work done by the man on the block during the motion.

$m_{b} = 2 k g, s = 40 m, a = 0.5 m . s e c^{2}$

So, force applied by the man on the box,

$F = m_{b} a$

$2 \times (0.5)$

$= 1 N$

$ω = F . S$

$= 1 \times 40$

$= 40 J$