A man moves on a straight horizontal road with a block of mass 2 kg in his hand. If he covers a distance of 40 m with an acceleration of $0.5 m / s^{2}$ , find the work done by the man on the block.

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Solution

Work done by the man, $W = \to F . \to s = F s c o s θ = (m a) (40) c o s 0^{\circ} = 2 \times 0.5 \times 40 ∴ W = 40 J$

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A man moves on a straight horizontal road with a block of mass 2 kg in his hand. If he covers a distance of 40 m with an acceleration of 0.5 m/s2, find the work done by the man on the block.

Work done by the man, W=→F.→s=Fs cosθ=(ma)(40)cos0∘=2×0.5×40∴W=40 J

A man moves on a straight horizontal road with a block of mass 2 kg in his hand. If he covers a distance of 40 m with an acceleration of $0.5 m / s^{2}$ , find the work done by the man on the block.

Work done by the man, $W = \to F . \to s = F s c o s θ = (m a) (40) c o s 0^{\circ} = 2 \times 0.5 \times 40 ∴ W = 40 J$