A man moves on a straight horizontal road with a block of mass 2 kg in his hand. If he covers a distance of 40 m with an acceleration of 0⋅5 m/s², find the work done by the man on the block during the motion.

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Solution

Given:
$Mass of the block, m = 2 kg Distance coverd by the man, s = 40 m Acceleration of the man, a = 0.5 m / s^{2}$
So, force applied by the man on the box,
$F = m a = 2 \times (0.5) = 1 N Work done by the man on the block, W = F \cdot S = 1 \times 40 = 40 J$

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A man moves on a straight horizontal road with a block of mass 2 kg in his hand. If he covers a distance of 40 m with an acceleration of 0⋅5 m/s2, find the work done by the man on the block during the motion.

Given: Mass of the block, m=2 kgDistance coverd by the man, s=40 mAcceleration of the man, a=0.5 m/s2 So, force applied by the man on the box, F=ma=2×0.5=1 NWork done by the man on the block, W=F·S=1×40=40 J

A man moves on a straight horizontal road with a block of mass 2 kg in his hand. If he covers a distance of 40 m with an acceleration of 0⋅5 m/s², find the work done by the man on the block during the motion.

Given:
$Mass of the block, m = 2 kg Distance coverd by the man, s = 40 m Acceleration of the man, a = 0.5 m / s^{2}$
So, force applied by the man on the box,
$F = m a = 2 \times (0.5) = 1 N Work done by the man on the block, W = F \cdot S = 1 \times 40 = 40 J$